golang syscall 例子

获取 Windows 的系统默认目录

Windows 系统目录函数请参考 MSDN：https://msdn.microsoft.com/en-us/library/windows/desktop/bb762181%28v=vs.85%29.aspx

package main

import (
	"fmt"
	"syscall"
	"unsafe"
)

var (
	shell         = syscall.MustLoadDLL("Shell32.dll")
	getFolderPath = shell.MustFindProc("SHGetFolderPathW")
)

const (
	CSIDL_DESKTOP = 0	//用户桌面默认目录
	CSIDL_APPDATA = 26	//用户AppData目录
)

func main() {
	b := make([]uint16, syscall.MAX_PATH)
	
    // https://msdn.microsoft.com/en-us/library/windows/desktop/bb762181%28v=vs.85%29.aspx
	// 这里第二个参数CSIDL_A必须定义为const，否则编译报错
	r, _, err := getFolderPath.Call(0, CSIDL_DESKTOP, 0, 0, uintptr(unsafe.Pointer(&b[0])))
	if uint32(r) != 0 {
		fmt.Sprintf("获取DIR错误：", err)
	}
	a_dir := syscall.UTF16ToString(b)

	r, _, err = getFolderPath.Call(0, CSIDL_APPDATA, 0, 0, uintptr(unsafe.Pointer(&b[0])))
	if uint32(r) != 0 {
		fmt.Sprintf("获取DIR错误：", err)
	}
	b_dir := syscall.UTF16ToString(b)

	fmt.Printf("目录ID：%d  目录地址：%s\n", CSIDL_DESKTOP, a_dir)
	fmt.Printf("目录ID：%d  目录地址：%s\n", CSIDL_APPDATA, b_dir)
}

💬 SHGetFolderPathW 的第二个参数必须定义为 const，否则编译不过

输出

目录ID：0  目录地址：C:\Users\kuuyee\Desktop
目录ID：26  目录地址：C:\Users\kuuyee\AppData\Roaming