有什么办法可以在搜索双链时优先展示某些路径下的内容块呀

把下面的代码放到 js 代码片段中

把 searchRefBlockSortBy(['你的路径']); 改成你自己的真实路径即可

searchRefBlockSortBy(['你的路径']);
function searchRefBlockSortBy(sortPaths) {
    const originalFetch = window.fetch;
    window.fetch = async function (url, init) {
        // 真正发请求
        const response = await originalFetch(url, init);

        // 只处理目标接口
        if (url.toString().toLowerCase().endsWith('/api/search/searchrefblock')) {
            // 克隆一份 response，用来读 body
            const cloned = response.clone();
            let bodyJson;
            try {
                bodyJson = await cloned.json();
            } catch (e) {
                // 如果不是 JSON，直接返回原始 response
                return response;
            }

            // 排序返回结果
            const blocks = bodyJson?.data?.blocks;
            if (Array.isArray(blocks)) {
                blocks.sort((a, b) => {
                    const hPathA = a.hPath || '';
                    const hPathB = b.hPath || '';
                    const isMatchedA = sortPaths.some(prefix =>
                        hPathA.startsWith(prefix.replace(/^\//,'')) || hPathA.includes(`/${prefix.replace(/^\//,'')}`)
                    );
                    const isMatchedB = sortPaths.some(prefix =>
                        hPathB.startsWith(prefix.replace(/^\//,'')) || hPathB.includes(`/${prefix.replace(/^\//,'')}`)
                    );
                    if (isMatchedA && !isMatchedB) return -1;
                    if (!isMatchedA && isMatchedB) return 1;
                    return 0;
                });

                // 把修改后的数据串回去，构造一个新的 Response
                const newBody = JSON.stringify(bodyJson);
                const { status, statusText, headers } = response;
                return new Response(newBody, { status, statusText, headers });
            }
        }

        // 默认返回原始 response
        return response;
    };
}