[每日 LeetCode] 83. Remove Duplicates from Sorted List

Description:

Given a sorted linked list, delete all duplicates such that each element appear only once.

Example 1:

Input: 1->1->2
Output: 1->2

Example 2:

Input: 1->1->2->3->3
Output: 1->2->3

思路：本题要求删除链表中重复的元素。比较简单，依次遍历链表节点并比较，若连续两个节点元素相等则直接修改指针即可。

C++ 代码

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        ListNode* curr = head;
        while(curr && curr->next){
            if (curr->val == curr->next->val){
                ListNode *temp = curr->next;
                curr->next = temp->next;
                delete temp;
            }
            else
                curr = curr->next;
        }
        return head;
    }
};

运行时间：12ms

运行内存：9.1M