北大acm 1007 Maya Calendar 解题报告

Maya Calendar

Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 33288 Accepted: 10153

Description

During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. From an old knotted message, professor discovered that the Maya civilization used a 365 day long year, called Haab, which had 19 months. Each of the first 18 months was 20 days long, and the names of the months were pop, no, zip, zotz, tzec, xul, yoxkin, mol, chen, yax, zac, ceh, mac, kankin, muan, pax, koyab, cumhu. Instead of having names, the days of the months were denoted by numbers starting from 0 to 19. The last month of Haab was called uayet and had 5 days denoted by numbers 0, 1, 2, 3, 4. The Maya believed that this month was unlucky, the court of justice was not in session, the trade stopped, people did not even sweep the floor.
For religious purposes, the Maya used another calendar in which the year was called Tzolkin (holly year). The year was divided into thirteen periods, each 20 days long. Each day was denoted by a pair consisting of a number and the name of the day. They used 20 names: imix, ik, akbal, kan, chicchan, cimi, manik, lamat, muluk, ok, chuen, eb, ben, ix, mem, cib, caban, eznab, canac, ahau and 13 numbers; both in cycles.
Notice that each day has an unambiguous description. For example, at the beginning of the year the days were described as follows:
1 imix, 2 ik, 3 akbal, 4 kan, 5 chicchan, 6 cimi, 7 manik, 8 lamat, 9 muluk, 10 ok, 11 chuen, 12 eb, 13 ben, 1 ix, 2 mem, 3 cib, 4 caban, 5 eznab, 6 canac, 7 ahau, and again in the next period 8 imix, 9 ik, 10 akbal . . .
Years (both Haab and Tzolkin) were denoted by numbers 0, 1, : : : , where the number 0 was the beginning of the world. Thus, the first day was:
Haab: 0. pop 0
Tzolkin: 1 imix 0
Help professor M. A. Ya and write a program for him to convert the dates from the Haab calendar to the Tzolkin calendar.

Input
The date in Haab is given in the following format:
NumberOfTheDay. Month Year
The first line of the input file contains the number of the input dates in the file. The next n lines contain n dates in the Haab calendar format, each in separate line. The year is smaller then 5000.

Output
The date in Tzolkin should be in the following format:
Number NameOfTheDay Year
The first line of the output file contains the number of the output dates. In the next n lines, there are dates in the Tzolkin calendar format, in the order corresponding to the input dates.

Sample Input
310. zac 00. pop 010. zac 1995

Sample Output
33 chuen 01 imix 09 cimi 2801

思路先将Haab日历转换为天数，然后换算为Tzolkin日历

#include <iostream>
using namespace std;
int main()
{
	int hdate,hyear,tdate=0,tyear=0,k;
	long sumdays,i,t;
	char mon[10],str[19][10]={"pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu","uayet"};
    char tstr[21][10]={"imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", "eznab", "canac","ahau" };
freopen("t.txt","rt",stdin);

cin&gt;&gt;t;
cout&lt;&lt;t&lt;&lt;endl;
while(t--)
{
   scanf("%d. %s %d",&amp;hdate,mon,&amp;hyear);   
   sumdays=hdate+1+hyear*365;     
   tyear=0;
  
   for(i=0;i&lt;19;i++)
	{
		if(strcmp(str[i],mon)==0)
		{
		 sumdays+=i*20;
		 break;
		}
	}
			 //以上为计算该Haab日历的总天数
   while(sumdays&gt;260)
   {
		tyear++;
		sumdays-=260;
   }           //换算为Tzolkin日历   i=sumdays%13;

   if(i==0)
	   i=13;

   k=sumdays%20;

   k--;          //因为天数从0开始所以需减一

   if(k==-1)
	   k=19;

   cout&lt;&lt;i&lt;&lt;" "&lt;&lt;tstr[k]&lt;&lt;" "&lt;&lt;tyear&lt;&lt;endl;
} 
return 0;

}