原文链接 [每日 LeetCode] 225. Implement Stack using Queues
Description:
Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Example:
MyStack stack = new MyStack();
stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false
Notes:
- You must use_only_standard operations of a queue -- which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
思路:本题是[每日 LeetCode] 232. Implement Queue using Stacks 镜像题,本题要求用队列结构实现队列的基本操作。由于队列先进先出的特性,考虑只使用一个队列完成操作,具体做法为:对每个栈的 push
操作后,对当前队列逆序,让队头始终保存刚刚压入的元素,如此一来即可实现栈的基本操作。
C++ 代码
class MyStack {
public:
/** Initialize your data structure here. */
MyStack() {
}
/** Push element x onto stack. */
void push(int x) {
temp.push(x);
for (int i=0; i<temp.size() - 1; i++){
temp.push(temp.front());
temp.pop();
}
}
/** Removes the element on top of the stack and returns that element. */
int pop() {
int tem = temp.front();
temp.pop();
return tem;
}
/** Get the top element. */
int top() {
return temp.front();
}
/** Returns whether the stack is empty. */
bool empty() {
return temp.empty();
}
private:
queue<int> temp;
};
/**
* Your MyStack object will be instantiated and called as such:
* MyStack* obj = new MyStack();
* obj->push(x);
* int param_2 = obj->pop();
* int param_3 = obj->top();
* bool param_4 = obj->empty();
*/
运行时间:4ms
运行内存:8.9M
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