原文链接 [每日 LeetCode] 232. Implement Queue using Stacks
Description:
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue(); queue.push(1); queue.push(2); queue.peek(); // returns 1 queue.pop(); // returns 1 queue.empty(); // returns false
Notes:
- You must use_only_standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
思路:本题要求用 stack 结构来实现队列的基本操作。由于队列的特点是先进先出,所以考虑使用两个 stack 来操作,一个 input 和一个 output,当 output 栈空时,从 input 栈中弹出元素压进 output 栈,如此一来即可实现后进的后出。
C++ 代码
class MyQueue { stack<int> input, output; public: /** Initialize your data structure here. */ MyQueue() { } /** Push element x to the back of queue. */ void push(int x) { input.push(x); } /** Removes the element from in front of queue and returns that element. */ int pop() { int temp = peek(); output.pop(); return temp; } /** Get the front element. */ int peek() { if (output.empty()) while(input.size()){ output.push(input.top()); input.pop(); } return output.top(); } /** Returns whether the queue is empty. */ bool empty() { return input.empty() && output.empty(); } }; /** * Your MyQueue object will be instantiated and called as such: * MyQueue* obj = new MyQueue(); * obj->push(x); * int param_2 = obj->pop(); * int param_3 = obj->peek(); * bool param_4 = obj->empty(); */
运行时间:4ms
运行内存:9M
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